N nfreidman New Member Joined Mar 15, 2012 Messages 15 Gender Female HSC 2012 Aug 25, 2012 #1 can someone please explain how to do this - the highest point of the trajectory of a body is 300m and its horizontal range is 5000m. Find the initial velocity and angle of projection. thank you!
can someone please explain how to do this - the highest point of the trajectory of a body is 300m and its horizontal range is 5000m. Find the initial velocity and angle of projection. thank you!
RishBonjour Well-Known Member Joined Aug 14, 2011 Messages 1,261 Gender Male HSC 2012 Aug 25, 2012 #2 does it land on the same plane? if so, you can divide range by 2. so at time t, y=300, x=2500. or alternatively, y=0, x=5000. do some substitutions, and you should get V and theta
does it land on the same plane? if so, you can divide range by 2. so at time t, y=300, x=2500. or alternatively, y=0, x=5000. do some substitutions, and you should get V and theta
S Sindivyn Member Joined Mar 4, 2012 Messages 194 Gender Male HSC 2012 Aug 25, 2012 #3 Do you have answers? want to be sure before posting
C cineti970128 Member Joined Apr 25, 2012 Messages 139 Gender Male HSC 2014 Aug 25, 2012 #4 I ve got V= 331.9m/s angle = 13.5 degrees