projectile question (1 Viewer)

[Da_Bomb]

ok one more..

A cannon is at the top of a 60m high cliff firing at a castle on top of an adjacent cliff 110m high. The cannon and castle are 200m apart horizontally.
The cannon balls hit 20s after firing.

(a) the initial velocity of the projectile.
(b) its initial horizontal vleocity.
(c) its initial vertical velocity.
(d) its range
(e) its max height above launch position.
(f) time taken to reazch max height.
(g) its time of flight.

 

[iMAN2]

So there is a cannonball fired from the castle as well?

 

[bored.of.u]

So there is a cannonball fired from the castle as well?

wth no

 

[shady145]

ok one more..

A cannon is at the top of a 60m high cliff firing at a castle on top of an adjacent cliff 110m high. The cannon and castle are 200m apart horizontally.
The cannon balls hit 20s after firing.

(a) the initial velocity of the projectile.
(b) its initial horizontal vleocity.
(c) its initial vertical velocity.
(d) its range
(e) its max height above launch position.
(f) time taken to reazch max height.
(g) its time of flight.

maybe you should try the question... obviuosly you havnt tried as two of the answers are whats in the question =/

 

[h3ll h0und]

maybe you should try the question... obviuosly you havnt tried as two of the answers are whats in the question =/

LOL...i think he got these questions from the surfing books. i remember doing these in class.

 

[weirdguy99]

Not sure if these are right...but

a) v=u+at, 0=u+(-9.8*20)
u=196m/s

let W = angle of elevation
tanW = 50/200
W=14degrees 2 minutes

b) 196cosW

c) 196sinW

d) s=u*t
s=(196cosW)x20
s= 3803m (I assumed that they wanted the FULL range of the projectile..not the range to the castle which would obviously be 200m)

e)v^2=u^2+2*a*s
0=(196sinW)^2+2*-9.8*s
s=115.247m

f)s=0.5*a*t^2
115.247=-4.9t
t=23.52s

g) 20s (kinda obvious)