*Before starting this part of the question break it down into bite-sized pieces.*
Part ii in summary is
Sphere

has equation
^{2}+\left(y-2\right)^{2}+\left(z-5\right)^{2}=1)
Sphere

has equation
Both of them use the fact that
^{2}+\left(y-b\right)^{2}+\left(z-c\right)^{2}=r^{2})
, where r is the radius and see the resemblence to a circle which is 2D because a sphere is 3D.
Plus, you need to find the equation of a circle and find its centre and radius. Which one would you do first?
If you look at the context of the question you will see that the centre for the x and y-axis are the same the only change is the z coordinates.
Thus, we will solve for the centre first.
Using what we know start with the fact that
Take away
^{2}+\left(y-2\right)^{2})
on both sides.
That leaves us with
Using difference of two squares we will have
Dividing by 3 we will have
=\frac{11}{3})
.

.
There you have found the centre of the intersection of the two spheres
)
.
Now, find the radius.
Draw a diagram that will look something like this.