Q11 (1 Viewer)

[Rafy]

Discuss your answers to Q11 here.

 

[duckysd]

Very easy.

 

[124]

so question e is it (16,4) and g you take out the 1/2 and leave with secx^2 to tan yeah?

 

[S1MZ8]

how about we discuss q16c, everyone who studied should get 15/15 for q11

 

[freeeeee]

E i got (0,6)
G i got 2

 

[duckysd]

e) Focus (0,6)

g) integral (o - pi/2) sec^2(x/2) has primitive 2tan(X/2)

Evaluate only at pi/2 since tan 0 = 0;

Answer is just 2.

 

[abs12345]

isnt it x^2 =4ay so a=4 and the vertex is (0,2) so the coordinates of the focus is (0,6) ?

 

[Timske]

so question e is it (16,4) and g you take out the 1/2 and leave with secx^2 to tan yeah?

e) F( 0 , 6)

g) 2

 

[Timske]

so question e is it (16,4) and g you take out the 1/2 and leave with secx^2 to tan yeah?

if the vertex is ( 0 , 2 ) and focus is ( 16 , 4 ) ...

 

[wootwoot1234]

was the length of the arc 16/2/3?

 

[Timske]

was the length of the arc 16/2/3?

Yeah should be

 

[freeeeee]

was the length of the arc 16/2/3?

ye

 

[wootwoot1234]

awesome!

 

[JChou]

when they asked for factorise, what if you solve for x? lol

 

[chillybags]

Did people get 50/3 cm for f??

 

[captainpigs]

nice

 

[megaman64]

Did people get 50/3 cm for f??

yes i got it

 

[Demise]

I'm unaware if I put 50 or 50/3 for f... It was obviously 50/3 and I'm sure I put it but I'm running it through my head now. FFS!