I integrated the found rateI had no idea what to do for d (ii)
I just did 0.4 x 10 = 4m = 4L LOL I'm pretty sure that's not correct.
Oh crap. I think I understand now.. is it 4m, so thus we divide our answer in (i) by 3?!?! ok no idk.
OMG Fark, Volume!!!!!!!!!!!!!! i didnt even see thatis dii)
volume=area v length
32.8 x 0.4/m/s x 12
1574.4??
what was cii? i forgotWas c)ii 440
How many tiles would Jay use altogether to make to first 20 rowswhat was cii? i forgot
Thats what I got.from part I) area = 32.8
II)D=SxT
=0.4x10= 4,
V=DxArea from part i)
= 32.8x4
=131.2
isnt that it?
i forgot my answer but you use Sum of AP.How many tiles would Jay use altogether to make to first 20 rows
I got 2440 to begin then got 440 haha
Is this the simpsons rule q?from part I) area = 32.8
II)D=SxT
=0.4x10= 4,
V=DxArea from part i)
= 32.8x4
=131.2
isnt that it?
Yep, then you had to find the volume of water flowing through in 10sec.Is this the simpsons rule q?
was this the how many rows can Justin make with 200 tiles?was q12 c) iii)- n=13
scared of miscalculation..
Thats what I got for both II forget what i got for I but im assuming it was 32.8from part I) area = 32.8
II)D=SxT
=0.4x10= 4,
V=DxArea from part i)
= 32.8x4
=131.2
isnt that it?
Well.. looks like i lost another mark -___-Thats what I got.
yeawas this the how many rows can Justin make with 200 tiles?
thats what i got.from part I) area = 32.8
II)D=SxT
=0.4x10= 4,
V=DxArea from part i)
= 32.8x4
=131.2
isnt that it?