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pt1

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HSC
2012
Hey how would you do this question part (III)?
Thanks
 

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2xL

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Gender
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2012
L = a + (K-1)d = a + Kd - d
K = a + (L-1)d = a + Ld - d

L - Kd = a - d
K - Ld = a -d

L - Kd = K - Ld
Kd - Ld = L - k
d(K - L) = L - K
d = -1
 

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