• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

question (1 Viewer)

mathsbrain

Member
Joined
Jul 16, 2012
Messages
161
Gender
Male
HSC
N/A
Q: find the number of ways that 6 different coloured balls
can be placed in 3 non-identical urns so that no urn is empty.

Answer 1: 540

Answer 2: 1080

Which one is correct and why?
 

GoldyOrNugget

Señor Member
Joined
Jul 14, 2012
Messages
583
Gender
Male
HSC
2012
When uncertain, bash out the cases!


If we put ONE ball in the first urn:
6C1 possibilities for this ball * (5C1 + 5C2 + 5C3 + 5C4), for each possible amount in the second urn

TWO balls in the first urn:

6C2 * (4C1 + 4C2 + 4C3)

THREE balls:

6C3 * (3C1 + 3C2)

FOUR balls:

6C4 * (2C1)

Add them all together, giving 540.
 

mathsbrain

Member
Joined
Jul 16, 2012
Messages
161
Gender
Male
HSC
N/A
My way of thinking is there are 3 cases:

Case 1: one urn has 4 balls, one urn has 1, another urn has 1.

So we do 6C4 * 2C1 * 1C1 to choose the balls, then arrange them so 3!, and we DO NOT divide by 2! because the urns are NOT IDENTICAL, is this correct? This is the part that i am confused, to divide by 2! or not. I think if the urns are identical then we divide.
 

GoldyOrNugget

Señor Member
Joined
Jul 14, 2012
Messages
583
Gender
Male
HSC
2012
You still divide by 2! because (4,1,1) is the same as (4,1,1).
 

mathsbrain

Member
Joined
Jul 16, 2012
Messages
161
Gender
Male
HSC
N/A
so for example,

Case 1: balls B,C,D,E in urn A, ball A in urn B and ball F in urn C
Case 2: balls B,C,D,E in urn A, ball F in urn B and ball A in urn C

Would you call that same outcome or different? I would say, they are same outcome IF urns are identical, but this is clearly not the case right? can carrotstick help?
 

jyu

Member
Joined
Nov 14, 2005
Messages
623
Gender
Male
HSC
2006
3(6c4)(2c1)(1c1)+3!(6c3)(3c2)(1c1)+1(6c2)(4c2)(2c2)=540
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top