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Find the number of ways in which the letters of the word EXTENSION can be arranged in a straight line so that no two vowels are next to each other
My answer: consonants can be arranged in 5! ways, vowels can then fit in 6 spots and thus can be arranged in 6x5x4x3 ways, therefore, total arrangements = (5!x6x5x4x3)/(2!x2!) = 10800 ways
Solution (CSSA): exaclty what i did but arranged the vowels first and fitted the consonants in giving 720 ways.
Am i right? if not why?
help is much appreciated
My answer: consonants can be arranged in 5! ways, vowels can then fit in 6 spots and thus can be arranged in 6x5x4x3 ways, therefore, total arrangements = (5!x6x5x4x3)/(2!x2!) = 10800 ways
Solution (CSSA): exaclty what i did but arranged the vowels first and fitted the consonants in giving 720 ways.
Am i right? if not why?
help is much appreciated
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