rates involving 2 or more variables (1 Viewer)

[Smilebuffalo]

The formula for the acceleration of a particle is given by A = 5x - e^2x +3, where x is the displacement of the particle. If the acceleration of the particle is at a constant rate of -9.8ms^-2, find the rate of change of its displacement when the displacement is -0.3m.

thanks

answer: -2.5ms^-1

 

[oly1991]

dA/dt=dA/dx.dx/dt

dA/dt = -9.8
dA/dx = 5 - 2e^2x

-9.8 = (5 - 2e^2x).dx/dt
dx/dt = -9.8/(5 - 2e^2x)
when x = -0.3
dx/dt = -2.511...ms^-1

 

[Smilebuffalo]

thank you very much!

 

[oly1991]

no worries