Reduction Formula Help (1 Viewer)

HyperComplexxx · Oct 3, 2011

How would you find I 100 ?

apollo1 · Oct 3, 2011

HyperComplexxx said:
How would you find I 100 ?

$I_{100} = \frac{100}{102}.\frac{99}{101}.\frac{98}{100}.\frac{97}{99}............\frac{1}{3}I_{0}$

HyperComplexxx · Oct 3, 2011

ooo no sh!t, silly me ...

apollo1 · Oct 3, 2011

then you cancel everything until you are left with:

$\frac{2}{102.101}.I_{0} = \frac{1}{5151}$

apollo1 · Oct 3, 2011

HyperComplexxx said:
ooo no sh!t, silly me ...

lol. better to make silly mistakes now than in 3 weeks time.

michaeljennings · Oct 3, 2011

HyperComplexxx said:
How would you find I 100 ?

This looks really familiar is it from baulko ext 2 2011 trial?

4025808 · Oct 3, 2011

michaeljennings said:
This looks really familiar is it from baulko ext 2 2011 trial?

yes that was from this year's baulko MX2 trial. that was a pretty easy question imo. It looked deceptively difficult though