A vessel is in the shape of a right circular cone with vertex downwards and axis vertical; the height of the vessel is 12m and the radius of its circular top is 8m. The vessel is being filled with water, the inflow of water is at the uniform rate 2m^3/min.
When the height if water is 'h' meters, find an expression for the radius 'r' meters of the water surface in terms if 'h', and prove that the volume V m^3 of water is V = (4pih^3)/27.
At what rate is the surface of the water rising when its depth is 3m?
Generally i can do related rates questions fine, but i'm having trouble starting this. Given that it is a right circular cone, I would have thought the the height should be the same as the radius...but the question states that h=12 and r=8, so i struggle to see how it is still a right circular cone...
When the height if water is 'h' meters, find an expression for the radius 'r' meters of the water surface in terms if 'h', and prove that the volume V m^3 of water is V = (4pih^3)/27.
At what rate is the surface of the water rising when its depth is 3m?
Generally i can do related rates questions fine, but i'm having trouble starting this. Given that it is a right circular cone, I would have thought the the height should be the same as the radius...but the question states that h=12 and r=8, so i struggle to see how it is still a right circular cone...