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Section II (4 Viewers)

julia21

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yeah 27 C) i had them as equal chance? hmm.. what you guys do for 25 A)?
i dont think they're equal chance the fisrt chick has 2/100 and the second can 2/200 so the first has double the prob but yeah pretty stupid q for 4 marks???i had -2x-9 for 25ai couldn't do 28c and ran out of time :( and i skipped the simpsons rule q and was going to come back but didnt ... also couldnt do 28 b part ii but over all thought it was ok needed more time ..... and the gov question was pretty irrelevant haha i said something about birth rate and schooling or something
 

mystiques4

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and the gov question was pretty irrelevant haha i said something about birth rate and schooling or something
I wrote that they would need to determine the age of children in the area if they were to consider opening a high school. I.E they need to check if there is a large amount of Year 4/5/6 students that will require a high school in the future, justifying the building of another school.
 

pooksta

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i think for the raffle ticket 27 c you could do a probaility tree , multiply along the lines and add to get her probability. i got marys prob. to be 2% chance and janes 1.99%
 

chrisvec

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i got mary having a 2/100 = 1/50 chance of winningwhilst jane was a 2/100 = 1/100 chance therefore mary has a greater chance
 

chrisvec

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with 26 a) ii) the IQR = 50% and there is 25% of scores under the lower quartile as as the 4 sections are broken up into quarters therefore 25% in each section
 
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with 26 a) ii) the IQR = 50% and there is 25% of scores under the lower quartile as as the 4 sections are broken up into quarters therefore 25% in each section
ffs I don't remember being taught that though it makes sense i guess. Lost marks now = 6. Probably more due to silly mistakes.
 

m3mphis

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so 75 percent right or not? i just looked and saw the upper quartile rang is in line with 5 hours, therefore anything below it must be 75 percent.
 

emma211

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so 75 percent right or not? i just looked and saw the upper quartile rang is in line with 5 hours, therefore anything below it must be 75 percent.
I'm pretty sure it was 75%

What did people write for 26 (a) (iii) ?

I wrote that it would be true if the same number of girls and boys were surveyed..dunno if thats right
 

walesluke

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i said if same number of boys and girls aswell.

overall this was a hard paper and i think 90+ is going to be a really good score.

mean is gonna be low so 80's will be scaled up into 90's maybe.

cause 06,07, and 08 95+ was good cause they were so much easier.

dont stress too much everyone. unless of course you were stupid enough to leave out the back page.
 

TaraBella

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I'm pretty sure it was 75%

What did people write for 26 (a) (iii) ?

I wrote that it would be true if the same number of girls and boys were surveyed..dunno if thats right
I said like it would be true if there were the same amount of outlyer girls int he 5-6 range as the small amount of boys in the 5-6 range. As it is more condensed for boys up in the 5-6 range, there would have to be a smaller amount of boys to have to accomidate to the amount of girls. Idk . lol I dont know if im right.
 

emma211

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I said like it would be true if there were the same amount of outlyer girls int he 5-6 range as the small amount of boys in the 5-6 range. As it is more condensed for boys up in the 5-6 range, there would have to be a smaller amount of boys to have to accomidate to the amount of girls. Idk . lol I dont know if im right.
haha i just got so confused by that answer.
 

aaronzimmermann

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emma211 said:
What did people write for 26 (a) (iii) ?

I wrote that it would be true if the same number of girls and boys were surveyed..dunno if thats right
I put it would be true if there was more girls than boys because the graph shows that boys spend longer on the internet than girls.
 

Intermission

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Yeah, it's more girls than boys. It's gotta be, if there is to be the same number of girls outside their interquartile range as there are boys close to their median.
 

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