Semester 1 Chatter Thread (2009) (14 Viewers)

[Ben Netanyahu]

yeah but see, the thing is

a) i dont know you
b) foreverpink is a tooliehead
c) bkm and i shall forever be mortal enemies. i am the organic chemist and she is not

sincerely
jim c ronshaw

 

[imsopostmodern]

i have no morphine

 

[ledzeppelin]

shit fuck cunt
i cannot simplify this derivative

 

[velox]

Vector calculus is easy, try harder.

 

[ledzeppelin]

Vector calculus is easy, try harder.

would you like to provide me with help?
Q3 part a). if so

 

[Ben Netanyahu]

i gave it to you about 20mins ago FP, you imbecile. the clock is messed up on bos.

furthermore, what statistical analysis would one use on excel to prove a correlation? anova?

 

[velox]

i gave it to you about 20mins ago FP, you imbecile. the clock is messed up on bos.

furthermore, what statistical analysis would one use on excel to prove a correlation? anova?

Um just find the correlation coefficient.

 

[ledzeppelin]

i gave it to you about 20mins ago FP, you imbecile. the clock is messed up on bos.

furthermore, what statistical analysis would one use on excel to prove a correlation? anova?

=correl gives you the correlation coefficient which indicates the strength and direction of any correlation

 

[ledzeppelin]

Um just find the correlation coefficient.

seriuzly halp me pleaSe

 

[jb_nc]

seriuzly halp me pleaSe

Possible derivation:
d/dx((x^2 y^2 (x^2-y^2))/(x^2+y^2))
| Factor out constants:
= | y^2 (d/dx((x^2 (x^2-y^2))/(x^2+y^2)))
| Use the quotient rule, d/dx(u/v) = (( du)/( dx))/v-(u ( dv)/( dx))/v^2, where u = x^2 (x^2-y^2) and v = x^2+y^2:
= | y^2 ((d/dx(x^2 (x^2-y^2)))/(x^2+y^2)-(x^2 (x^2-y^2) (d/dx(x^2+y^2)))/(x^2+y^2)^2)
| Use the product rule, d/dx(u v) = v ( du)/( dx)+u ( dv)/( dx), where u = x^2 and v = x^2-y^2:
= | (y^2 (x^2 (d/dx(x^2-y^2))+(x^2-y^2) (d/dx(x^2))))/(x^2+y^2)-(x^2 y^2 (x^2-y^2) (d/dx(x^2+y^2)))/(x^2+y^2)^2
| Differentiate the sum term by term:
= | (y^2 (x^2-y^2) (d/dx(x^2)))/(x^2+y^2)-(x^2 y^2 (x^2-y^2) (d/dx(x^2)+d/dx(y^2)))/(x^2+y^2)^2+(x^2 y^2 (d/dx(x^2-y^2)))/(x^2+y^2)
| The derivative of x^2 is 2 x:
= | -(x^2 y^2 (x^2-y^2) (d/dx(x^2)))/(x^2+y^2)^2-(x^2 y^2 (x^2-y^2) (d/dx(y^2)))/(x^2+y^2)^2+(x^2 y^2 (d/dx(x^2-y^2)))/(x^2+y^2)+(2 x y^2 (x^2-y^2))/(x^2+y^2)
| The derivative of x^2 is 2 x:
= | -(x^2 y^2 (x^2-y^2) (d/dx(y^2)))/(x^2+y^2)^2+(x^2 y^2 (d/dx(x^2-y^2)))/(x^2+y^2)+(2 x y^2 (x^2-y^2))/(x^2+y^2)-(2 x^3 y^2 (x^2-y^2))/(x^2+y^2)^2
| The derivative of y^2 is zero:
= | (x^2 y^2 (d/dx(x^2-y^2)))/(x^2+y^2)+(2 x y^2 (x^2-y^2))/(x^2+y^2)-(2 x^3 y^2 (x^2-y^2))/(x^2+y^2)^2
| Differentiate the sum term by term and factor out constants:
= | (x^2 y^2 (d/dx(x^2)-d/dx(y^2)))/(x^2+y^2)+(2 x y^2 (x^2-y^2))/(x^2+y^2)-(2 x^3 y^2 (x^2-y^2))/(x^2+y^2)^2
| The derivative of x^2 is 2 x:
= | -(x^2 y^2 (d/dx(y^2)))/(x^2+y^2)+(2 x y^2 (x^2-y^2))/(x^2+y^2)+(2 x^3 y^2)/(x^2+y^2)-(2 x^3 y^2 (x^2-y^2))/(x^2+y^2)^2
| The derivative of y^2 is zero:
= | (2 x y^2 (x^2-y^2))/(x^2+y^2)+(2 x^3 y^2)/(x^2+y^2)-(2 x^3 y^2 (x^2-y^2))/(x^2+y^2)^2

 

[ledzeppelin]

Possible derivation:
d/dx((x^2 y^2 (x^2-y^2))/(x^2+y^2))
| Factor out constants:
= | y^2 (d/dx((x^2 (x^2-y^2))/(x^2+y^2)))
| Use the quotient rule, d/dx(u/v) = (( du)/( dx))/v-(u ( dv)/( dx))/v^2, where u = x^2 (x^2-y^2) and v = x^2+y^2:
= | y^2 ((d/dx(x^2 (x^2-y^2)))/(x^2+y^2)-(x^2 (x^2-y^2) (d/dx(x^2+y^2)))/(x^2+y^2)^2)
| Use the product rule, d/dx(u v) = v ( du)/( dx)+u ( dv)/( dx), where u = x^2 and v = x^2-y^2:
= | (y^2 (x^2 (d/dx(x^2-y^2))+(x^2-y^2) (d/dx(x^2))))/(x^2+y^2)-(x^2 y^2 (x^2-y^2) (d/dx(x^2+y^2)))/(x^2+y^2)^2
| Differentiate the sum term by term:
= | (y^2 (x^2-y^2) (d/dx(x^2)))/(x^2+y^2)-(x^2 y^2 (x^2-y^2) (d/dx(x^2)+d/dx(y^2)))/(x^2+y^2)^2+(x^2 y^2 (d/dx(x^2-y^2)))/(x^2+y^2)
| The derivative of x^2 is 2 x:
= | -(x^2 y^2 (x^2-y^2) (d/dx(x^2)))/(x^2+y^2)^2-(x^2 y^2 (x^2-y^2) (d/dx(y^2)))/(x^2+y^2)^2+(x^2 y^2 (d/dx(x^2-y^2)))/(x^2+y^2)+(2 x y^2 (x^2-y^2))/(x^2+y^2)
| The derivative of x^2 is 2 x:
= | -(x^2 y^2 (x^2-y^2) (d/dx(y^2)))/(x^2+y^2)^2+(x^2 y^2 (d/dx(x^2-y^2)))/(x^2+y^2)+(2 x y^2 (x^2-y^2))/(x^2+y^2)-(2 x^3 y^2 (x^2-y^2))/(x^2+y^2)^2
| The derivative of y^2 is zero:
= | (x^2 y^2 (d/dx(x^2-y^2)))/(x^2+y^2)+(2 x y^2 (x^2-y^2))/(x^2+y^2)-(2 x^3 y^2 (x^2-y^2))/(x^2+y^2)^2
| Differentiate the sum term by term and factor out constants:
= | (x^2 y^2 (d/dx(x^2)-d/dx(y^2)))/(x^2+y^2)+(2 x y^2 (x^2-y^2))/(x^2+y^2)-(2 x^3 y^2 (x^2-y^2))/(x^2+y^2)^2
| The derivative of x^2 is 2 x:
= | -(x^2 y^2 (d/dx(y^2)))/(x^2+y^2)+(2 x y^2 (x^2-y^2))/(x^2+y^2)+(2 x^3 y^2)/(x^2+y^2)-(2 x^3 y^2 (x^2-y^2))/(x^2+y^2)^2
| The derivative of y^2 is zero:
= | (2 x y^2 (x^2-y^2))/(x^2+y^2)+(2 x^3 y^2)/(x^2+y^2)-(2 x^3 y^2 (x^2-y^2))/(x^2+y^2)^2

thanking you, but the first line is just xy(x^2-y^2), not (x^2 y^2 (x^2-y^2))

 

[CountVonChocula]

thanking you, but the first line is just xy(x^2-y^2), not (x^2 y^2 (x^2-y^2))

LOL
ol

 

[jb_nc]

thanking you, but the first line is just xy(x^2-y^2), not (x^2 y^2 (x^2-y^2))

d/dx((x y(x) (x^2-y(x)^2))/(x^2+y(x)^2))
| Use the quotient rule, d/dx(u/v) = (( du)/( dx))/v-(u ( dv)/( dx))/v^2, where u = x y(x) (x^2-y(x)^2) and v = x^2+y(x)^2:
= | (d/dx(x y(x) (x^2-y(x)^2)))/(x^2+y(x)^2)-(x y(x) (x^2-y(x)^2) (d/dx(x^2+y(x)^2)))/(x^2+y(x)^2)^2
| Differentiate the sum term by term:
= | (d/dx(x y(x) (x^2-y(x)^2)))/(x^2+y(x)^2)-(x y(x) (x^2-y(x)^2) (d/dx(x^2)+d/dx(y(x)^2)))/(x^2+y(x)^2)^2
| The derivative of x^2 is 2 x:
= | -(x y(x) (x^2-y(x)^2) (d/dx(y(x)^2)))/(x^2+y(x)^2)^2+(d/dx(x y(x) (x^2-y(x)^2)))/(x^2+y(x)^2)-(2 x^2 y(x) (x^2-y(x)^2))/(x^2+y(x)^2)^2
| Use the chain rule, d/dx(y(x)^2) = ( du^2)/( du) ( du)/( dx), where u = y(x) and ( du^2)/( du) = 2 u:
= | -(2 x y(x)^2 (x^2-y(x)^2) (d/dx(y(x))))/(x^2+y(x)^2)^2+(d/dx(x y(x) (x^2-y(x)^2)))/(x^2+y(x)^2)-(2 x^2 y(x) (x^2-y(x)^2))/(x^2+y(x)^2)^2
| The derivative of y(x) is y'(x):
= | (d/dx(x y(x) (x^2-y(x)^2)))/(x^2+y(x)^2)-(2 x y(x)^2 (x^2-y(x)^2) y'(x))/(x^2+y(x)^2)^2-(2 x^2 y(x) (x^2-y(x)^2))/(x^2+y(x)^2)^2
| Use the product rule, d/dx(u v) = v ( du)/( dx)+u ( dv)/( dx), where u = x and v = y(x) (x^2-y(x)^2):
= | (x (d/dx(y(x) (x^2-y(x)^2)))+y(x) (x^2-y(x)^2) (d/dx(x)))/(x^2+y(x)^2)-(2 x y(x)^2 (x^2-y(x)^2) y'(x))/(x^2+y(x)^2)^2-(2 x^2 y(x) (x^2-y(x)^2))/(x^2+y(x)^2)^2
| Use the product rule, d/dx(u v) = v ( du)/( dx)+u ( dv)/( dx), where u = y(x) and v = x^2-y(x)^2:
= | (x (y(x) (d/dx(x^2-y(x)^2))+(x^2-y(x)^2) (d/dx(y(x)))))/(x^2+y(x)^2)+(y(x) (x^2-y(x)^2) (d/dx(x)))/(x^2+y(x)^2)-(2 x y(x)^2 (x^2-y(x)^2) y'(x))/(x^2+y(x)^2)^2-(2 x^2 y(x) (x^2-y(x)^2))/(x^2+y(x)^2)^2
| Differentiate the sum term by term and factor out constants:
= | (x y(x) (d/dx(x^2)-d/dx(y(x)^2)))/(x^2+y(x)^2)+(x (x^2-y(x)^2) (d/dx(y(x))))/(x^2+y(x)^2)+(y(x) (x^2-y(x)^2) (d/dx(x)))/(x^2+y(x)^2)-(2 x y(x)^2 (x^2-y(x)^2) y'(x))/(x^2+y(x)^2)^2-(2 x^2 y(x) (x^2-y(x)^2))/(x^2+y(x)^2)^2
| The derivative of x^2 is 2 x:
= | -(x y(x) (d/dx(y(x)^2)))/(x^2+y(x)^2)+(x (x^2-y(x)^2) (d/dx(y(x))))/(x^2+y(x)^2)+(y(x) (x^2-y(x)^2) (d/dx(x)))/(x^2+y(x)^2)-(2 x y(x)^2 (x^2-y(x)^2) y'(x))/(x^2+y(x)^2)^2+(2 x^2 y(x))/(x^2+y(x)^2)-(2 x^2 y(x) (x^2-y(x)^2))/(x^2+y(x)^2)^2
| Use the chain rule, d/dx(y(x)^2) = ( du^2)/( du) ( du)/( dx), where u = y(x) and ( du^2)/( du) = 2 u:
= | -(2 x y(x)^2 (d/dx(y(x))))/(x^2+y(x)^2)+(x (x^2-y(x)^2) (d/dx(y(x))))/(x^2+y(x)^2)+(y(x) (x^2-y(x)^2) (d/dx(x)))/(x^2+y(x)^2)-(2 x y(x)^2 (x^2-y(x)^2) y'(x))/(x^2+y(x)^2)^2+(2 x^2 y(x))/(x^2+y(x)^2)-(2 x^2 y(x) (x^2-y(x)^2))/(x^2+y(x)^2)^2
| The derivative of y(x) is y'(x):
= | (x (x^2-y(x)^2) (d/dx(y(x))))/(x^2+y(x)^2)+(y(x) (x^2-y(x)^2) (d/dx(x)))/(x^2+y(x)^2)-(2 x y(x)^2 y'(x))/(x^2+y(x)^2)-(2 x y(x)^2 (x^2-y(x)^2) y'(x))/(x^2+y(x)^2)^2+(2 x^2 y(x))/(x^2+y(x)^2)-(2 x^2 y(x) (x^2-y(x)^2))/(x^2+y(x)^2)^2
| The derivative of y(x) is y'(x):
= | (y(x) (x^2-y(x)^2) (d/dx(x)))/(x^2+y(x)^2)-(2 x y(x)^2 y'(x))/(x^2+y(x)^2)+(x (x^2-y(x)^2) y'(x))/(x^2+y(x)^2)-(2 x y(x)^2 (x^2-y(x)^2) y'(x))/(x^2+y(x)^2)^2+(2 x^2 y(x))/(x^2+y(x)^2)-(2 x^2 y(x) (x^2-y(x)^2))/(x^2+y(x)^2)^2
| The derivative of x is 1:
= | -(2 x y(x)^2 y'(x))/(x^2+y(x)^2)+(x (x^2-y(x)^2) y'(x))/(x^2+y(x)^2)-(2 x y(x)^2 (x^2-y(x)^2) y'(x))/(x^2+y(x)^2)^2+(2 x^2 y(x))/(x^2+y(x)^2)-(2 x^2 y(x) (x^2-y(x)^2))/(x^2+y(x)^2)^2+(y(x) (x^2-y(x)^2))/(x^2+y(x)^2)

 

[withoutaface]

Possible derivation:
d/dx((x^2 y^2 (x^2-y^2))/(x^2+y^2))
| Factor out constants:
= | y^2 (d/dx((x^2 (x^2-y^2))/(x^2+y^2)))
| Use the quotient rule, d/dx(u/v) = (( du)/( dx))/v-(u ( dv)/( dx))/v^2, where u = x^2 (x^2-y^2) and v = x^2+y^2:
= | y^2 ((d/dx(x^2 (x^2-y^2)))/(x^2+y^2)-(x^2 (x^2-y^2) (d/dx(x^2+y^2)))/(x^2+y^2)^2)
| Use the product rule, d/dx(u v) = v ( du)/( dx)+u ( dv)/( dx), where u = x^2 and v = x^2-y^2:
= | (y^2 (x^2 (d/dx(x^2-y^2))+(x^2-y^2) (d/dx(x^2))))/(x^2+y^2)-(x^2 y^2 (x^2-y^2) (d/dx(x^2+y^2)))/(x^2+y^2)^2
| Differentiate the sum term by term:
= | (y^2 (x^2-y^2) (d/dx(x^2)))/(x^2+y^2)-(x^2 y^2 (x^2-y^2) (d/dx(x^2)+d/dx(y^2)))/(x^2+y^2)^2+(x^2 y^2 (d/dx(x^2-y^2)))/(x^2+y^2)
| The derivative of x^2 is 2 x:
= | -(x^2 y^2 (x^2-y^2) (d/dx(x^2)))/(x^2+y^2)^2-(x^2 y^2 (x^2-y^2) (d/dx(y^2)))/(x^2+y^2)^2+(x^2 y^2 (d/dx(x^2-y^2)))/(x^2+y^2)+(2 x y^2 (x^2-y^2))/(x^2+y^2)
| The derivative of x^2 is 2 x:
= | -(x^2 y^2 (x^2-y^2) (d/dx(y^2)))/(x^2+y^2)^2+(x^2 y^2 (d/dx(x^2-y^2)))/(x^2+y^2)+(2 x y^2 (x^2-y^2))/(x^2+y^2)-(2 x^3 y^2 (x^2-y^2))/(x^2+y^2)^2
| The derivative of y^2 is zero:
= | (x^2 y^2 (d/dx(x^2-y^2)))/(x^2+y^2)+(2 x y^2 (x^2-y^2))/(x^2+y^2)-(2 x^3 y^2 (x^2-y^2))/(x^2+y^2)^2
| Differentiate the sum term by term and factor out constants:
= | (x^2 y^2 (d/dx(x^2)-d/dx(y^2)))/(x^2+y^2)+(2 x y^2 (x^2-y^2))/(x^2+y^2)-(2 x^3 y^2 (x^2-y^2))/(x^2+y^2)^2
| The derivative of x^2 is 2 x:
= | -(x^2 y^2 (d/dx(y^2)))/(x^2+y^2)+(2 x y^2 (x^2-y^2))/(x^2+y^2)+(2 x^3 y^2)/(x^2+y^2)-(2 x^3 y^2 (x^2-y^2))/(x^2+y^2)^2
| The derivative of y^2 is zero:
= | (2 x y^2 (x^2-y^2))/(x^2+y^2)+(2 x^3 y^2)/(x^2+y^2)-(2 x^3 y^2 (x^2-y^2))/(x^2+y^2)^2

My eyes burn

 

[runoutofsleep]

this page looks like the matrix

 

[jb_nc]

d/dy((x y (x^2-y^2))/(x^2+y^2))
| Factor out constants:
= | x (d/dy((y (x^2-y^2))/(x^2+y^2)))
| Use the quotient rule, d/dy(u/v) = (( du)/( dy))/v-(u ( dv)/( dy))/v^2, where u = y (x^2-y^2) and v = x^2+y^2:
= | x ((d/dy(y (x^2-y^2)))/(x^2+y^2)-(y (x^2-y^2) (d/dy(x^2+y^2)))/(x^2+y^2)^2)
| Use the product rule, d/dy(u v) = v ( du)/( dy)+u ( dv)/( dy), where u = y and v = x^2-y^2:
= | (x ((x^2-y^2) (d/dy(y))+y (d/dy(x^2-y^2))))/(x^2+y^2)-(x y (x^2-y^2) (d/dy(x^2+y^2)))/(x^2+y^2)^2
| Differentiate the sum term by term:
= | (x (x^2-y^2) (d/dy(y)))/(x^2+y^2)-(x y (x^2-y^2) (d/dy(x^2)+d/dy(y^2)))/(x^2+y^2)^2+(x y (d/dy(x^2-y^2)))/(x^2+y^2)
| The derivative of y is 1:
= | -(x y (x^2-y^2) (d/dy(x^2)))/(x^2+y^2)^2-(x y (x^2-y^2) (d/dy(y^2)))/(x^2+y^2)^2+(x y (d/dy(x^2-y^2)))/(x^2+y^2)+(x (x^2-y^2))/(x^2+y^2)
| The derivative of x^2 is zero:
= | -(x y (x^2-y^2) (d/dy(y^2)))/(x^2+y^2)^2+(x y (d/dy(x^2-y^2)))/(x^2+y^2)+(x (x^2-y^2))/(x^2+y^2)
| The derivative of y^2 is 2 y:
= | (x y (d/dy(x^2-y^2)))/(x^2+y^2)-(2 x y^2 (x^2-y^2))/(x^2+y^2)^2+(x (x^2-y^2))/(x^2+y^2)
| Differentiate the sum term by term and factor out constants:
= | (x y (d/dy(x^2)-d/dy(y^2)))/(x^2+y^2)-(2 x y^2 (x^2-y^2))/(x^2+y^2)^2+(x (x^2-y^2))/(x^2+y^2)
| The derivative of x^2 is zero:
= | -(x y (d/dy(y^2)))/(x^2+y^2)-(2 x y^2 (x^2-y^2))/(x^2+y^2)^2+(x (x^2-y^2))/(x^2+y^2)
| The derivative of y^2 is 2 y:
= | -(2 x y^2)/(x^2+y^2)-(2 x y^2 (x^2-y^2))/(x^2+y^2)^2+(x (x^2-y^2))/(x^2+y^2)

 

[ledzeppelin]

d/dy((x y (x^2-y^2))/(x^2+y^2))
| Factor out constants:
= | x (d/dy((y (x^2-y^2))/(x^2+y^2)))
| Use the quotient rule, d/dy(u/v) = (( du)/( dy))/v-(u ( dv)/( dy))/v^2, where u = y (x^2-y^2) and v = x^2+y^2:
= | x ((d/dy(y (x^2-y^2)))/(x^2+y^2)-(y (x^2-y^2) (d/dy(x^2+y^2)))/(x^2+y^2)^2)
| Use the product rule, d/dy(u v) = v ( du)/( dy)+u ( dv)/( dy), where u = y and v = x^2-y^2:
= | (x ((x^2-y^2) (d/dy(y))+y (d/dy(x^2-y^2))))/(x^2+y^2)-(x y (x^2-y^2) (d/dy(x^2+y^2)))/(x^2+y^2)^2
| Differentiate the sum term by term:
= | (x (x^2-y^2) (d/dy(y)))/(x^2+y^2)-(x y (x^2-y^2) (d/dy(x^2)+d/dy(y^2)))/(x^2+y^2)^2+(x y (d/dy(x^2-y^2)))/(x^2+y^2)
| The derivative of y is 1:
= | -(x y (x^2-y^2) (d/dy(x^2)))/(x^2+y^2)^2-(x y (x^2-y^2) (d/dy(y^2)))/(x^2+y^2)^2+(x y (d/dy(x^2-y^2)))/(x^2+y^2)+(x (x^2-y^2))/(x^2+y^2)
| The derivative of x^2 is zero:
= | -(x y (x^2-y^2) (d/dy(y^2)))/(x^2+y^2)^2+(x y (d/dy(x^2-y^2)))/(x^2+y^2)+(x (x^2-y^2))/(x^2+y^2)
| The derivative of y^2 is 2 y:
= | (x y (d/dy(x^2-y^2)))/(x^2+y^2)-(2 x y^2 (x^2-y^2))/(x^2+y^2)^2+(x (x^2-y^2))/(x^2+y^2)
| Differentiate the sum term by term and factor out constants:
= | (x y (d/dy(x^2)-d/dy(y^2)))/(x^2+y^2)-(2 x y^2 (x^2-y^2))/(x^2+y^2)^2+(x (x^2-y^2))/(x^2+y^2)
| The derivative of x^2 is zero:
= | -(x y (d/dy(y^2)))/(x^2+y^2)-(2 x y^2 (x^2-y^2))/(x^2+y^2)^2+(x (x^2-y^2))/(x^2+y^2)
| The derivative of y^2 is 2 y:
= | -(2 x y^2)/(x^2+y^2)-(2 x y^2 (x^2-y^2))/(x^2+y^2)^2+(x (x^2-y^2))/(x^2+y^2)

Where are you generating this from?
Thanks for the halp, but after figuring out what the final line of that actually says, I've actually got it in a simpler form than this, just not sure if it can go any further
I'd give some rep but must spread some around first apparently

 

[jb_nc]

Where are you generating this from?
Thanks for the halp, but after figuring out what the final line of that actually says, I've actually got it in a simpler form than this, just not sure if it can go any further
I'd give some rep but must spread some around first apparently

wolfram alpha search engine

it fuckin rules

just felt like posting walls of text though

if you post first line into the bar it will generate a latex form which is easy to read

 

[goony]

matlab algebra toolbox needed imo.

 

[withoutaface]

matlab algebra toolbox needed imo.

Fuck matlab's a piece of shit. I hate it so hard.

Also I did the railcorp personality test. Do they actually cull people based on that shit, cause it's fucking hard to see how you could make yourself look like a balanced human being from the responses they asked you to choose.