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show question for trig. (1 Viewer)

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tanx= tan(x/2+x/2)
=(2tanx/2)/(1-tan2x/2)
=2t/1-t2
then just draw up a right angle triangle and find an expression for the hypotenuse
 

tommykins

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bossleymaths said:
if t=tan x/2 , show that sinx=2t / 1+t^2
sinx = 2sinx/2.cosx/2
= [2sinx/2.cosx/2]/sin²x+cos²x
= [2tanx/2]/1+tan²x/2 dividing everything by cos²x/2
= 2t/1+t²
 

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