Thank you, this helps heaps! Would you also happen to have an actual explanation as to what is going on? I have also done the same thing for a lead acid cell and talked about how the ions move throughout the battery etc. Would you have any information similar to that?
No worries. I think what happens is you have KOH as your electrolyte in a porous medium within the middle of the button cell. Zinc acts as an anode on one end of the cell and silver oxide is the cathode at the other end of the cell. The Zinc basically reacts with the OH
- ions from the KOH electrolyte to form Zinc Oxide, water and releases two electrons which travels within the electrolyte I think. This is the oxidation process
The silver oxide then uses these two electrons from the oxidation of zinc and also reacts with water to form silver solid and hydroxide ions (which probably are released back into the KOH electrolyte).
These oxidation and reduction reactions consequently result in electrochemical cell being formed which have a net voltage of 1.5 V.
Perhaps this following diagram can help you visualise the actual structure of it a bit better:
https://dc.edu.au/wp-content/uploads/silver-oxide-button-cell.png