Solving question (1 Viewer)
- Thread starter cutemouse
- Start date
Aquawhite
Retiring
That's a really good problem solving question. I personally don't know how to solve it, but I'd like to see some others give it a go.
Re-write as
y^2-x^2=2009
Factorise using difference of 2 squares:
(y-x)(y+x) =2009
If x and y are both integers, then so are y-x and y+x.
Find the prime factorisation of 2009 and then check what all the possibilities for x and y are.
y^2-x^2=2009
Factorise using difference of 2 squares:
(y-x)(y+x) =2009
If x and y are both integers, then so are y-x and y+x.
Find the prime factorisation of 2009 and then check what all the possibilities for x and y are.