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sdx91

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if you think you lost <30 marks then you will get over 75% :)
 

MrKim

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Well why dont someone ask a question that they wanted to know about, then others can help and give their answers. Compare and voila.

As for me, i wanted to know the answer in regards to the monthly payment part (ii) i think it was. I got something like 100~ something, i dont know if this is correct. Someone know?
 

Rampager

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Question 9 b) ii) $975.

Question 10 a) 5ln5 - 4

Question 7 a) e^(3) and e^(-1)

Question 6c) 18.75(PI) units^2

Question 6b)i) 20
ii) t = 10
iii) t = 6
iv) forget.
 
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ewasemma

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Hey guys just wondering.. what would an 86/120 be roughly as a moderated mark for maths. thanks
 

Rampager

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ewasemma said:
Hey guys just wondering.. what would an 86/120 be roughly as a moderated mark for maths. thanks
Band 4, unlikely Band 5.
 

BackCountrySnow

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Rampager said:
Question 6b)
iii) t = 6
yes i cbf quoting the ppl saying it isnt.
but here is why it is t=6:

what is acceleration?
It is the change in velocity over time.

And how do we measure this change?
oh, through the gradient.

yes, and when is the gradient 0?
umm, at the maximum, when 't' equals zero?

oh wow, correct.
 

minijumbuk

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chook 05 said:
was question #9 c) (ii) = 1/6kb^4 units below axis?
f'(x) = k(b2x - x3/3)
f(x) = k(b2x2 - x4/12) + C

When x = b, y = 0

0 = k(b4/2 - b4/12) + C
C = - 5b4k/12

f(x) = k(b2x2 - x4/12) + - 5b4k/12

When x = 0,
f(x) = - 5b4k/12
Therefore 5b4k/12 below x-axis
 

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