space problem (1 Viewer)

[byakuya kuchiki]

just after launch an astronaut experiences an acceleration of 5g. two weeks earlier, at a fun park, the astronaut went around a 10m horizontal bend at 72kmh in a roller coaster. what is the ratio of the rocket launch to the acceleration at the fun park?
help is greatly appreciated. =]

 

[micuzzo]

just after launch an astronaut experiences an acceleration of 5g. two weeks earlier, at a fun park, the astronaut went around a 10m horizontal bend at 72kmh in a roller coaster. what is the ratio of the rocket launch to the acceleration at the fun park?
help is greatly appreciated. =]

at launch: 5g = 5 x 9.8=49m/s/s

now around bend: F=mv^2/r

BUT: F=ma

so ma=mv^2/r

therefore: a=v^2/r which is the centripetal acc. formula..

then just plug it in:

v=72kmh = 20m/s

so 20^2/10 = 40

ratio = 49:40

answer seems a bit odd tho... i think its rite...

 

[byakuya kuchiki]

thanks. =DD

 

[micuzzo]

do u know if the answer is correct

 

[L]

the mysteries of time and space

 

[Dx_God]

working out is fine.