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Statistics question wtf (1 Viewer)

Shadowdude

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its econ 1203 - BES/Statistics/Something

a lot of probability/numbers/interpreting graphs etc



and i love reporting goodwin for a ban 10 minutes after he signs up ahhhahhhahhhh
ECON1203? Hmm, that's a Commerce core isn't it?
 

b00m

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correct, although economics and some other courses(?) also seem to do it as their core
 

b00m

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Q8) Helen the auditor one.

I'm not terribly sure unless I read up fully.

But it appears to be:



where 1.28 is z-value for 20% significance (80% confidence )

That means whatever her estimate is, there is an 80% probability it is in the interval



Answer: 12.8 not guaranteed correct.
and ye this turned out to be incorrect :(
its alright though i somehow got 9/10 thnks for the halp gais
 

cutemouse

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How can I calculate this if a standardised normal random variable (Z) of -8 isn't included in the cumulative standardised normal probabilities table in the appendix of my book.

What the fuck.
Use the Taylor series expansion.... (joke -- You'd require like 30 terms for 4dp accuracy)
 

study-freak

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Q8) Helen the auditor one.

I'm not terribly sure unless I read up fully.

But it appears to be:



where 1.28 is z-value for 20% significance (80% confidence )

That means whatever her estimate is, there is an 80% probability it is in the interval



Answer: 12.8 not guaranteed correct.
You need to use 0.1 quantile of the standard normal distribution because the confidence interval is two sided.
And I think "margin of error"=half of confidence interval length? in which case we wouldn't have times two in the front. Depends on the definition.
 

study-freak

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Let X denote the outstanding balances of customers of a firm. From past experiences X is well aproximated by a normal distribution with mean 45 and variance 100. If an auditor takes a random sample of 36 accounts what is the probability that the mean balance will be less than 45? (Your answer should be correct to one decimal place.)

gais, howd u do this one?^ or if not, where do i find the theory in the book.. im lagging by like 4 chapters lol ._.
mean balance~N(45,100/36) approximately by the Central Limit Theorem.
Note that the mean does not change and therefore the answer is simply 0.5 by symmetry of the normal density function about the mean.
 

cutemouse

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And I think "margin of error"=half of confidence interval length? in which case we wouldn't have times two in the front. Depends on the definition.
Yeah if CI = [x bar +/- z_{1-alpha/2} rho/sqrt(n)]

then the margin of error m = z_{1-alpha/2} rho\sqrt{n}

ie. CI = [x bar +/- m]

(or whatever respective estimator you want)
 

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