Stuck! (1 Viewer)

[DannyT]

Okay this is a really simple question but I just can't get the answer for some reason (I put my calculator to rad). Either the answer's wrong or I'm a complete dumbass.

find the definite integral of 2sec^2x with terminals 1 and -3^0.5/2
the answer is 5.5 to 1 dp, I got 8.7.

 

[lyounamu]

Okay this is a really simple question but I just can't get the answer for some reason (I put my calculator to rad). Either the answer's wrong or I'm a complete dumbass.

find the definite integral of 2sec^2x with terminals 1 and -3^0.5/2
the answer is 5.5 to 2 dp, I got 8.7.

def intg of 2sec^2(x) = 2 [tanx] put the values in and you should get 5.46643... = 5.47 to 2 d.p.

 

[DannyT]

I still do not understand why my answer is different...baha

 

[lyounamu]

I still do not understand why my answer is different...baha

hm

show me your working out.

 

[DannyT]

yeh k 2[tanx] with terminals of 1 and -3^0.5/2

with my calculator in rad..
2[1.5574...- (-2.773...)]
2[4.330869378..]
8.661....

 

[lyounamu]

yeh k 2[tanx] with terminals of 1 and -3^0.5/2

with my calculator in rad..
2[1.5574...- (-2.773...)]
2[4.330869378..]
8.661....

hm
it's more like

2 [1.5574... - (-1.17581074...)]

be careful: -3^0.5/2 = (-3^0.5)/2

 

[DannyT]

ahhh such an error! thanks
i'll try not to be so careless next time =P