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[xV1P3R]

I was wondering if this was possible, having one of the bounds to be

 

[untouchablecuz]

it is possible

consult this post:

http://community.boredofstudies.org...revising-marathon-hsc-10-a/9.html#post4928546

 

[xV1P3R]

Wow Thanks. There's just one bit I don't understand

Why do you get a->pi
What's the significance of pi that you can do that?

Otherwise, really helpful!

 

[untouchablecuz]

Wow Thanks. There's just one bit I don't understandWhy do you get a->pi
What's the significance of pi that you can do that?

Otherwise, really helpful!

well, notice that tan(x/2) is undefined when x=pi

integrating [0-->2pi] will lead us into trouble

so we split the interval up into 2 regions:

[0-->a] [a-->2pi]

then we take the limit as a--->pi,

understand?

 

[xV1P3R]

Doesn't this mean "a" can be any number between 0 and 2pi because we are just adding two areas under the curve?

Is it because we realise values of tan(a/2) go from positive to negative as we go a<pi to a>pi

Maybe this is way beyond my knowledge =/

Thanks anyway for your help [Can't seem to rep you, need to spread around]