i got ph = 2.9dafidav said:for that hcl qs
this is how i did it and got ph of 5
n=0.01 x 0.01
=0.0001
and then it was diluted to 100ml, so dilute factor of 10
so u divide 0.0001 by 10 and get 0.00001
so ph=-log[H+]
so =-log 0.00001
=5
but so many people sayings its 3