the hence find in part b i assume wants us to use part a (1 Viewer)

[aimsneetno1]

but i dont know exactly how i wud do that

any help appreciated

 

[mmmmmmmmaaaaaaa]

When you let u = (lnx)^2 and v' = x ... after doing the integration by parts process, you will notice the second part (the one where you still need to integrate) is actually xlnx

 

[aimsneetno1]

thanks yh makes sense, lowkey reminds me of recurrence reactions

When you let u = (lnx)^2 and v' = x ... after doing the integration by parts process, you will notice the second part (the one where you still need to integrate) is actually xlnx

 

[chilli 412]

(sorry ignore top of the page with cosh inverse)