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Three Preliminary questions (1 Viewer)

Dragonmaster262

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Q) Calculate the empirical formula:

93.7% carbon
6.3% hydrogen

Q) Write the chemical formula of the following:

a) nickel hydrogen carbonate
b) iron(2) sulfate heptahydrate
 

kaz1

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Been a while since I done this.

n=m/M
n[carbon]=93.7/12.01=7.8
n[hydrogen]=6.3/1=6.3

7.8/6.3=26/21

therefore C26H21
 

randomnessss

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Q) Write the chemical formulas of the following:

a) nickel hydrogen carbonate: Ni(HCO3)2
b) iron(2) sulfate heptahydrate FeSO4.7H2O
 

rufous

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As kaz1 suggested but use 1.008 for H and you get a ratio which is 1.248:1 and this may be rounded to 1.25:1 ultimately giving you a ratio of 5:4 ie C5H4.
 

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