Trig Equation (1 Viewer)

xibu34 · Mar 1, 2023

Can anybody help me with this trig equation q it's got me pretty stuck

Drongoski · Mar 1, 2023

$\therefore \frac {tan \frac {\pi}{4} + tan\theta}{1-tan\frac {\pi}{4} tan\theta} = 3 \frac{ tan \frac{\pi}{4} - tan\theta}{1+ tan{\frac {\pi}{4}}tan\theta} \\ \\ \therefore \frac {1+tan\theta}{1-tan\theta} = 3\times \frac {1-tan\theta}{1+ tan\theta} \\ \\ \therefore (1+tan\theta)^2 = 3(1-tan\theta)^2$

etc . . . . etc

Typo corrected; thanks to tywebb

tywebb · Mar 1, 2023

Drongoski · Mar 1, 2023

T

tywebb said:
View attachment 37824

Thanks; typo when in a hurry!

Trig Equation (1 Viewer)

xibu34

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Drongoski

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tywebb

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Drongoski

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