T Thylacine New Member Joined May 1, 2012 Messages 18 Gender Undisclosed HSC N/A May 28, 2014 #1 A triangle ABC is right-angled at C. Angle BAC = theta. D is the point on AB such that DC is perpendicular to AB. i) You are given that 2AD + 7BC = 5AB Simplify: 2cos theta + 7tan theta ii) Hence find theta
A triangle ABC is right-angled at C. Angle BAC = theta. D is the point on AB such that DC is perpendicular to AB. i) You are given that 2AD + 7BC = 5AB Simplify: 2cos theta + 7tan theta ii) Hence find theta
P photastic Well-Known Member Joined Feb 11, 2013 Messages 1,848 Gender Male HSC 2014 May 29, 2014 #2 Part i) It's good to draw a diagram. After finding this, ii is a simple trig question but since it's a triangle, theta is only between 0 and 90 degrees.
Part i) It's good to draw a diagram. After finding this, ii is a simple trig question but since it's a triangle, theta is only between 0 and 90 degrees.
T Thylacine New Member Joined May 1, 2012 Messages 18 Gender Undisclosed HSC N/A May 29, 2014 #3 Thanks just have to work out theta.
