Trig ratios halp! (1 Viewer)

[ohexploitable]

EDIT: lawl, i typed the first question wrong...

 

[Lukybear]

 

[shaon0]

4([tan(x)]^2+1)=3tan(x)+5 [from (sin(x))^2+(cos(x))^2=1]
4(tan(x))^2-3tan(x)-1=0
(4tan(x)+1)(tan(x)-1)=0
4tan(x)=-1 or tan(x)=1
x=-atan(1/4) or pi/4 now just input the cycles in 360 deg

 

[Lukybear]

second one:

 

[gurmies]

second one:

-1/4 my friend

 

[ohexploitable]

lawl, i typed the first question wrong...

 

[life92]

4 cos^2 - 4 sin = 1
4 (1 - sin^2) - 4 sin = 1
4 - 4sin^2 - 4sin = 1
4sin^2 + 4sin -3 = 0
(2sin-1)(2sin+3)=0

therefore, sinx = 1/2, sinx = -3/2
for sin x = 1/2 ,, x = 30, 150

for sinx = -3/2, there are no solutions as -1< sinx <1

 

[ohexploitable]

Thanks guys!