Trigonometry Help (1 Viewer)

[Farhanthestudent005]

Simplify this trig equation

Please help urgently thank you

 

[jimmysmith560]

Would this be correct?

 

[yanujw]

Either jimmysmith560's answer, or that the equation is supposed to be 1 - (sin^2xcos^2x/sin^2x)

In which case you get 1 - cos^2x = sin^2x

 

[Farhanthestudent005]

Would this be correct?
View attachment 30752

Yes but it is telling me to prove it.How do I do so?

 

[jimmysmith560]

Yes but it is telling me to prove it.How do I do so?

As in prove that is equal to the answer I gave?

 

[Trebla]

View attachment 30751
Simplify this trig equation

Please help urgently thank you

Can you please post your questions in the Maths forum, NOT the secondary education forum

I have had to move your thread.

 

[Farhanthestudent005]

As in prove that View attachment 30753 is equal to the answer I gave?

Yes

 

[Farhanthestudent005]

Can you please post your questions in the Maths forum, NOT the secondary education forum

I have had to move your thread.

Ok thank you, my apologies

 

[jimmysmith560]

I realised I was overthinking this question, here's what you need to do:

Bring the sin^2x up, it becomes csc^2x, we get

Expand. After expanding you will get:

Switch the first csc^2x back to its original form (turn it back to sin^2x), you will get:

The 2 sin^2x's cancel each other out, meaning you'll end up with , which is consistent with the first answer.

First time using so please bear with me.