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I did that but it’s 576 apparently_ _ _ _ _ _ _ _. 8 seats to sit on. Mariya must be in seat 1 and Aofa can't be in seat 8, so for now we will put her on the second seat:
M A _ _ _ _ _ _. Then you got the 3 ppl that gotta be together so :
M A c m h _ _ _ _. For those 3 ppl, they have 4 patterns in which they can sit, and they can be arranged in 3!, so can the other 3 random ppl. So you got 4 x 3! x 3! Then we also gotta consider Asofa since he/she can also sit in the 7th or 6th seat or whatever seat but the last: This means she can sit in the 2nd, 3rd, 4th, 5th, 6th and 7th seat, so 6 seats she can sit in total
therefore: 4 x 3! x 3! x 6 = 864
place mariya in seat 1, think of cooper, manny and hafsa as one 'person', so now there are 5 effective people, there are only 4 possibilities for seat 8, then there is 4! for the rest of the seats. Then multiply by 3! for coop, manny and hafsa. so it is 4x4!x3!=576.I did that but it’s 576 apparently