Just cut the beams AB, BC and CD diagonally. Then if you take the moments about A, F(AB) and F(CD) go through A so they don't count. The only force that counts is F(BC), but we know the moment about A must be 0, meaning F(BC) = 0.
OR
You can do method of joints at C, since there are no vertical forces F(BC) = 0, because sum of vertical forces has to equal 0 at every joint.