Using logs to find n (1 Viewer)

[liquid_soda]

I'm having a bit of trouble here
500 000 x 1.004375^n -[10 000 (1.004375^n -1)]/ 0.004375
How do I isolate and find n?

 

[Shadowdude]

I'm having a bit of trouble here
500 000 x 1.004375^n -[10 000 (1.004375^n -1)]/ 0.004375
How do I isolate and find n?

???


If so, well... you can't because there's no equation to solve.

 

[InteGrand]

???


If so, well... you can't because there's no equation to solve.

I'm guessing the minus sign was meant to be an equals sign (typo)? (Looks like a consumer arithmetic maths Q.)

 

[liquid_soda]

Apologies for the typo

Yup it's consumer, asking about when the amount owning is equal to zero

 

[Squar3root]

I got (2dp)

 

[liquid_soda]

I got (2dp)

that's it, ~57 months, how is your working out?

 

[Squar3root]

that's it, ~57 months, how is your working out?

it was really just algebra

I divided both sides by 10000
Multiplied both sides by 0.004375
Divided every term by 1.004375^n
and got 1.004375^n = 1.28
and used logs to get n = 56.24

 

[liquid_soda]

thanks man

 

[liquid_soda]

To clarify, am I allowed to take out the bracket then later take when factoring?
So that becomes

??

 

[Squar3root]

To clarify, am I allowed to take out the bracket then later take when factoring?
So that becomes

??

where did the "0.004375" term go?

no

 

[liquid_soda]

where did the "0.004375" term go?

no

times it to both sides so

 

[Squar3root]

times it to both sides so

if you did the algebra correctly, yes you should arrive at the same answer

 

[liquid_soda]

sigh, I don't know what to do with the brackets
help...

 

[InteGrand]

sigh, I don't know what to do with the brackets
help...

Maybe to make it clearer, let's just write .

Then the equation you got is .

Therefore,









(using the logarithm law on the RHS)



.

The integer answer is then .

 

[liquid_soda]

haha, I confused myself big time but got there in the end. Thanks everyone for the help