boredsatan
Member
- Joined
- Mar 23, 2017
- Messages
- 572
- Gender
- Male
- HSC
- 1998
What is the cost per 100 mL of soft drink if 2.25 L of the soft drink cost $1.90
approx. 8cents (to nearest cent)What is the cost per 100 mL of soft drink if 2.25 L of the soft drink cost $1.90
How would you work it out. I'm a little rusty with these kind of word problemsapprox. 8cents (to nearest cent)
Do you ever go to school?How would you work it out. I'm a little rusty with these kind of word problems
Why are you asking me if I go to school or not. I thought I had to do 190/22.5 because it was converting from mL to LDo you ever go to school?
How many 100mL in 2.25L?
2250/100
= 22.5
Then just divide the total price by 22.5
1.90/22.5 = 0.084444
= 8 cents
Because you're always posting in school hours.Why are you asking me if I go to school or not. I thought I had to do 190/22.5 because it was converting from mL to L
At what rate (in km/h) would a train be travelling if it covered 32.5 km in 15 minutes
I didn't have school todayBecause you're always posting in school hours.
But yeah, that works too, just remember you converted dollars into cents and that the 22.5 is how many 100mL are in 2.25L -> I wouldn't do it that way because the units get confusing
Then you get 8.4444
Which you have to remember is now in cents
You apparently never have school...I didn't have school today
what sort of a joke was that? It definitely wasn't funnyYou apparently never have school...
anyone?state the transformations from 1/x to 3/(x-1) + 2
Is it a dilation by factor of 3 from x axis or y axis?
Any help would be greatly appreciatedanyone?
bumpAny help would be greatly appreciated
You can find c = 2 considering that a/(x-b)^2 doesn't equal 0 so y can't equal c, and since y can't equal 2, then c = 2.y = a/(x-b)^2 + c
Given that the y intercept is (0,-1) and that an asymptote exists at y = 2, find the values of a, b, and c
4It is known that the straight line y = 4x-4 touches the curve y = x^2 at the point (2,4). Find the instantaneous rate of change of y with respect to x at the point (2,4) on the curve y = x^2
I was about to ask how you knew that straight away then i realized they gave you the value in the tangent anyways lol