Velocity and Acc Question HSC 1997 (1 Viewer)

Drewk · Oct 19, 2013

http://snag.gy/pLUT9.jpg
Trying this past hsc question using 1/2v^2
because we r given v i squared both sides then got 2xe^-x^4
then i would differentiate and mul by 1/2 but i don't think that gets me to the answer
Please help

Samir97 · Oct 19, 2013

When you square it the power becomes -2x^2 not x^4 because two powers would simply multiply so 2 x -x^2 is -2x^2

HeroicPandas · Oct 19, 2013

$\frac{1}{2}v^2 = xe^{-2x^2} \\ \\ \therefore a = e^{-2x^2} - (4x)(x) e^{-2x^2} \\ \\ \therefore a = e^{-2x^2} - 4x^2 e^{-2x^2}$

factorise and ur done

Samir97 · Oct 19, 2013

Velocity and Acc Question HSC 1997 (1 Viewer)

Drewk

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Samir97

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HeroicPandas

Heroic!

Samir97

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