• Best of luck to the class of 2024 for their HSC exams. You got this!
    Let us know your thoughts on the HSC exams here
  • YOU can help the next generation of students in the community!
    Share your trial papers and notes on our Notes & Resources page
MedVision ad

Vertical Circle Question - Please Help (1 Viewer)

OreoMcFlurry

Member
Joined
Jul 13, 2021
Messages
40
Gender
Male
HSC
2021
Hey Everyone, I was just doing a question from a physics paper based on vertical circles and I just don't understand this at all:
1633682992604.png

I'd be awesome if someone could show the working required to get the answer because I'm seriously lost whenever it comes to vertical circles rip.
Thank you very much.
 

Lith_30

o_o
Joined
Jun 27, 2021
Messages
158
Location
somewhere
Gender
Male
HSC
2022
Uni Grad
2025
We know that the passengers have to feel weightlessness at the top of the loop, therefore the centripetal force must be equal to the gravitational force.


Then we need to use conservation of energy to find a relationship between the height and the velocity



Since we know that the cart will be at the top of the loop, we can take the final height to be 16, and we can sub in the velocity that we got in the previous steps.



By subtracting 16 from 20 we get 4, which means A is the answer.
 

OreoMcFlurry

Member
Joined
Jul 13, 2021
Messages
40
Gender
Male
HSC
2021
We know that the passengers have to feel weightlessness at the top of the loop, therefore the centripetal force must be equal to the gravitational force.


Then we need to use conservation of energy to find a relationship between the height and the velocity



Since we know that the cart will be at the top of the loop, we can take the final height to be 16, and we can sub in the velocity that we got in the previous steps.



By subtracting 16 from 20 we get 4, which means A is the answer.
Damn, thank you very much! It makes a lot of sense now that you've explained it :)
 

notme123

Well-Known Member
Joined
Apr 14, 2020
Messages
997
Gender
Male
HSC
2021
We know that the passengers have to feel weightlessness at the top of the loop, therefore the centripetal force must be equal to the gravitational force.


Then we need to use conservation of energy to find a relationship between the height and the velocity



Since we know that the cart will be at the top of the loop, we can take the final height to be 16, and we can sub in the velocity that we got in the previous steps.



By subtracting 16 from 20 we get 4, which means A is the answer.
to simplify you can make the top of the loop the ground so that you only need to do mgd=1/2 mv^2 when doing LCE and you get d=4 if v=8.85...
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top