ie the right one.x^2 = y ^2/3
V = pi [int] y^2/3 dy with limits of 1 and 0
V = pi [3/5 * y ^ 5/3 ] with limits of 1 and 0
V = pi [3/5 - 0]
V = 3pi/5 units^3
FUCK SO TRUE !!!!!!!!!LOL. I can't believe i forgot that!
+ 1.
Lol; i still don't know how to use it.In the time it took me to work out how to use the equation editor, everyone else had already posted the answer lol