answer is 8pi/3 u^3tommykins said:method/working out?
or are they expecting us to do shells for y = sqrtx and minus that from shells for y = x/2 ?
volume of a shell = 2 pi x y dytommykins said:Oh, it's that simple?
How'd you get 2y² - y³ ?
munch0r said:volume of a shell = 2 pi x y dy
so for y = x/2
x = 2y
so 2pi (2y^2)dy
and for y = sqrtx
x = y^2
so 2pi (y^3) dy
I did that once in a 3unit testPoad said:Heh, I remember that question. I actually got a negative answer. >_>
yes, verified it using slices, got the same answer...tacogym27101990 said:is the answer 8pi/3 u^3??
it was either a really easy question or i got it wrong
Same, and i somehow got ful marks xDmidifile said:I did that once in a 3unit test
I just absolute valued it when I was running out of time