Whats the solution to this? (1 Viewer)

FesuY · Mar 1, 2022

Screen Shot 2022-03-01 at 11.30.56 am.png

The question asks, Find the equation of the tangent to (the picture) if x= -1.
I got 5y+2x+27=0, but supposdly its wrong.

jklol · Mar 1, 2022

5sqrt(x^2) -4 is just x^(5/2) - 4 then you differntitate that and sub in -1 to find the gradient of the tangent at that point. you also gotta find the y value so substitute x into the orginal equation to find y and then use y_1-y=m(x-x_1) to find the equation

5uckerberg · Mar 1, 2022

Fellas this question $\sqrt[5]{x^{2}}-4=x^{\frac{2}{5}}-4$
Differentiate that and you will have $\frac{2}{5x^{\frac{3}{5}}}$
Put x=-1 and you will have $\frac{2}{5}$
There, we have $y+3=-\frac{2}{5}\left(x+1\right)$ . There is a calculation error from $\sqrt[5]{x^{2}}-4=x^{\frac{2}{5}}-4$ when you subbed in x=-1 and thought you got -1-4=-5. That is why you supposedly got it wrong.

Whats the solution to this? (1 Viewer)

FesuY

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jklol

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5uckerberg

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