how big a change is yr 11 maths to yr 10 maths (1 Viewer)

[bleakarcher]

i did it on a piece of paper next to me lol

 

[SpiralFlex]

isnt that just the integration taught in 2 unit maths

Correct. Which method did you use?

 

[bleakarcher]

i see wat u mean by foundation though. i couldnt graph that if i wanted to...

 

[bleakarcher]

i seperated the integrand to form two integralz, one of which was easily calculable, the other i had to use integration by substitution

 

[SpiralFlex]

i seperated the integrand to form two integralz, one of which was easily calculable, the other i had to use integration by substitution

Care to show me? I don't know what you mean by separated. This can be done using a clever 2U method.

 

[bleakarcher]

A=integral[(e^x+e^(-x)-e^(-x))/(e^x+e^(-x))] from x= 0 to 2
=integral[1] from x=0 to 2 -integral[e^(-x)/(e^x+e^(-x))] from x=0 to 2

 

[bleakarcher]

i thought u were going to give me a harder question lol. is this 2 unit maths btw? coz it seemz more like 3 unit maths?

 

[SpiralFlex]

A=integral[(e^x+e^(-x)-e^(-x))/(e^x+e^(-x))] from x= 0 to 2
=integral[1] from x=0 to 2 -integral[e^(-x)/(e^x+e^(-x))] from x=0 to 2

I believe you got your final answer wrong.

 

[bleakarcher]

how lol?

 

[SpiralFlex]

how lol?

Check your final answer carefully.

 

[bleakarcher]

i did lol itz right

 

[SpiralFlex]

i did lol itz right

But your final answer is wrong.

 

[bleakarcher]

wat final answer. the one i gave a page ago? u confirmed lol?

 

[SpiralFlex]

wat final answer. the one i gave a page ago? u confirmed lol?

Nope, I said your working was correct.

 

[Mature Lamb]

Do you have a strong foundation of your topics? I would be willing to bet that if I ask you an integration question right now, you will not be able to answer it.

Why don't you believe him?

 

[SpiralFlex]

Why don't you believe him?

I do believe him. I don't believe he has anything to worry about.

 

[bleakarcher]

it is confirmed
the answer is:
A=(1/2)ln[(e^4+1)/2e^4]+2

 

[bleakarcher]

i believe in my answerz. maths is a concrete study lol. i just repeated the integral on the opposite side of that same piece of paper and got the same answer.

 

[SpiralFlex]

it is confirmed
the answer is:
A=(1/2)ln[(e^4+1)/2e^4]+2

Very good. You have past the test. You shall do fine in Year 11.

 

[bleakarcher]

i knew u were fuking wif me lol. y waste my time?