legit where did i go wrong, hella confused its probably one of the subs.This was the intended method.
or is this a possible alternate form? desmos ain't registering it for some reason tho
legit where did i go wrong, hella confused its probably one of the subs.This was the intended method.
Ngl I can’t even follow your solutionlegit where did i go wrong, hella confused its probably one of the subs.
or is this a possible alternate form? desmos ain't registering it for some reason tho
pls use LATEXlet x = tan u
x/ sec^2u / x^2 === > tan^3 u ===> tanusec^2u - tanu let tan u = z, z^2/2 + ln |cos u| lowkey messed it up, say where plz
or PAPERpls use LATEX
desmos not looking right, what happened in my subs bruhlegit where did i go wrong, hella confused its probably one of the subs.
or is this a possible alternate form? desmos ain't registering it for some reason tho
Super small typing error here.
botched the algebra.let x = tan u
x/ sec^2u / x^2 === > tan^3 u ===> tanusec^2u - tanu let tan u = z, z^2/2 + ln |cos u| lowkey messed it up, say where plz
Seen it b4 but didn’t know it was from Stanford!Really cool integral from stanford which a lot of people have probably seen before:
thanks for picking that upSuper small typing error here.
wtf is this accounttfw you can't even do basic algebra smh
fuck latexmore integrals
my lil bro apparentlywtf is this account
mmm yes sexy latex completedmore integrals
more integrals
the classic integral-calculator.com integral that no one bothers doing.mmm yes sexy latex completed
Thats as simple as it gets I think (you can usually simplify if the inverse is in the brackets) also try using \cos^{-1}(x) to get imo looks a lot betterwhats in term of u im having a bit of a mental breakdown
i do better latex smhwhats in term of u im having a bit of a mental breakdown