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MX2 Integration Marathon (6 Viewers)

idkkdi

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This was the intended method.
legit where did i go wrong, hella confused its probably one of the subs.

or is this a possible alternate form? desmos ain't registering it for some reason tho
 

vernburn

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legit where did i go wrong, hella confused its probably one of the subs.

or is this a possible alternate form? desmos ain't registering it for some reason tho
Ngl I can’t even follow your solution
 

idkkdi

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legit where did i go wrong, hella confused its probably one of the subs.

or is this a possible alternate form? desmos ain't registering it for some reason tho
desmos not looking right, what happened in my subs bruh
 

Qeru

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Really cool integral from stanford which a lot of people have probably seen before:

 

idkkdi

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let x = tan u
x/ sec^2u / x^2 === > tan^3 u ===> tanusec^2u - tanu let tan u = z, z^2/2 + ln |cos u| lowkey messed it up, say where plz
botched the algebra.

but basically my way.
you sub in x = tan u.
u get ucot^2 u.
and by parts it.
this works right? @vernburn
 

notme123

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whats in term of u im having a bit of a mental breakdown
 

Qeru

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whats in term of u im having a bit of a mental breakdown
Thats as simple as it gets I think (you can usually simplify if the inverse is in the brackets) also try using \cos^{-1}(x) to get imo looks a lot better
 

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