how did you integrate sec cubed
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MX2 Integration Marathon (1 Viewer)
- Thread starter dan964
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Split it
yes ik the sec integrates to the first part but what about the second term
oh dont worry i found out how, by parts right
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this is probs a stupid q to ask and Ive asked this b4 but i dont think anyone answered but are these integrals just for fun, to deepen your understanding of the topic, or questions they could genuinely ask is a 4u hsc (without build up or previous questions).
They can ask everything here with build up only (or make it a last question like the 2014 hsc).
idekkedi
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I guess you like being mentally challenged...
How did you change the color lol
Directrix
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Wrong account lol
Directrix
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idekkedi
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Packing I see...
yesDo you mean
}}{\sqrt{x}}\ dx &= 2\int{e^u\sin(u+a)\ du} \qquad \text{where $u=\sqrt{x}$} \\ &= e^{\sqrt{x}}\left[\sin(\sqrt{x}+a)-\cos(\sqrt{x}+a)\right] + C \end{align*})
Surely theres no elementary anti-derivative to thisAt first, I thought you meant a much more difficult problem:
\]}{\sqrt{x}}\ dx)
None that I am aware of.
... that isnt the integral.Though I can give a 1 line answer:
\]}{\sqrt{x}}\ dx = F(x) \quad \text{where} \quad \frac{dF}{dx} = \frac{\sin\[e^{\sqrt{x}}(\sqrt{x}+a)\]}{\sqrt{x}})
am i missing something? this doesn't look like a one line answer.