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Jerryclover

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A lot of the questions you posted have errors in them. I hope you're not trolling
 

CM_Tutor

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How does one do part a?
If the middle term in the AP is , and we take , then the three sides of the triangle are, in increasing order, . Now, which of these must be opposite the angle given as 120o? Draw a diagram and recognise that you can use the cosine rule...
 

Jerryclover

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If you have specific examples of errors, post them and I will check.
The 9th post. The entire question doesn't work. a.) should be 2ln(x^2+3x)+c.

The 10th post, M and N coordinates shout be (-1,1) and (1,1) respectively.

If i'm wrong please correct me, but i double checked on wolfram alpha
 

CM_Tutor

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The 9th post. The entire question doesn't work. a.) should be 2ln(x^2+3x)+c.

The 10th post, M and N coordinates shout be (-1,1) and (1,1) respectively.

If i'm wrong please correct me, but i double checked on wolfram alpha
The 9th post has had a note added to note that there is a fault in it, as is posted above. The function should be


The 10th post, M and N are two of the three points of intersection of the parabloa and the circle . The points and lie on the circle but not the parabola.
 

CM_Tutor

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for b), i got stuck on , how can i write that in terms of sin?
For an AP, we need


from which we can find .

For (b), we have that the common difference is and so the next term after is


as you found. To answer in terms of , we need to eliminate the term by using the result established above, that , so the term is

 

Jerryclover

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Solution posted above. You need to use the condition that was established in part (a) that links and and allows you to find the specific value of .
Cheers. That connection was hard to find. Seems more like an ext1 question honestly
 

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