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Are those js the initial rates tho? Isnt the forward rxn technically increasing in B?For the second one, shifting to the right means the rate of the forward reaction (A + B ---> C) is faster / higher than that of the reverse reaction. Prior to returning to equilibrium, graph A has rate forward > rate reverse (moving right) while (B) has rate reverse > rate forward.
ur looking at gradientAre those js the initial rates tho? Isnt the forward rxn technically increasing in B?
Why r we looking at the gradient? the y axis is rate not concentratiohif its shifting to the right, then the reverse reactiion
ur looking at gradient
no as in i thought u were making the mistake of looking at the gradient or smn. mbmbView attachment 44415
also why is the answer to this A and not B