For Q 13, adding aqueous NaOH to a saturated Mg(OH)2 solution will lead to further precipitation of Mg(OH)2 (s) and with a decrease in the concentration of magnesium ions and an increase in the concentration of hydroxide ions such that [Mg2+][OH-]2 remains constant. This assumes that the sodium hydroxide solution was sufficiently concentrated that the effect of its addition was an increase in the hydroxide ion concentration that more than compensated for the dilution effect on the magnesium ion concentration. If the NaOH was extremely dilute then the result could be a solution of magnesium hydroxide is no longer saturated... but that's unlikely. Option (B) appears based on this possibility, but it's not literally true because (even in that case) the solubility hasn't changed, it's just that the solution has been diluted sufficiently to no longer be saturated. To me, none of the answers are good but (A) is the best choice available.