2026 HSC CHAT (7 Viewers)

[m_avi]

Guests make an account pls

As always , once mentioned they disappear...

 

[cristal]

yeah no its sorta cooked u cant delete accounts or change usernames

I thought you could under certain circumstances though (unlikely in this scenario)
Ngl I should have created a diff account too bc I'm way way too easy to find

 

[Socialism]

I thought you could under certain circumstances though (unlikely in this scenario)
Ngl I should have created a diff account too bc I'm way way too easy to find

no no u can

its just not like other websites where u can just change your handle or something

 

[safowan191]

how come the 2025 chat is so unhinged

 

[cristal]

how come the 2025 chat is so unhinged

think it's bc it was revived by those from 2024 and not so much the actual 2025'ers

 

[m_avi]

HELPP I CANT DO THESEE AHSHFHFJ

 

[NotBamboo]

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HELPP I CANT DO THESEE AHSHFHFJ

wait i gotta destroy my brothers in a game real quick get back to u in a sec

 

[Study to success]

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HELPP I CANT DO THESEE AHSHFHFJ

What textbook did u get it from

 

[Study to success]

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HELPP I CANT DO THESEE AHSHFHFJ

I think there supposed to be like a semicircle/ hyperbola thing. Maybe try graphing it on Desmos so u have a rough idea on how it’s supposed to look. I think maybe finding the vertex and intercepts of the equation in the denominator can help u find the domain and range

 

[cristal]

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HELPP I CANT DO THESEE AHSHFHFJ

Denominator has to be positive (inside the squareroot, not the result of the square root) and not 0 so make an inequality
Factorise from there
Smthing along the lines of that

 

[Study to success]

Denominator has to be positive and not 0 so make an unequality
Factorise from there
Smthing along the lines of that

Yeah that’s right and then u make the equation greater and equal to 0 I think . Idk if that right but then u just solve for x with the inequality sign

 

[cheesynooby]

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HELPP I CANT DO THESEE AHSHFHFJ

domain:
1. solve the quadratic and identify its concavity to find the x values where it is negative e.g. if it has x intercepts at x = -2 and 2, and is concave up the quadratic is negative between x = -2 and 2. since u cant square root a negative and cant divide by 0, that gives u the domain (x < -2, x > 2)

range:
2. find the range of the quadratic by finding the y coord of the vertex. e.g. vertex at (1, 3) and concave down = range: y ≤ 3
3. square root that (keeping in mind u can't square root a negative)-> 0 ≤ y ≤ sqrt3
4. find the reciprocal of that (a graph of y = 1/x could be useful - imagine the range of 1/x if you could only plug in values between 0 and sqrt3 (from step 3) -> y ≥ 1/sqrt3

 

[cristal]

What textbook did u get it from

looks like cambridge btw

 

[cheesynooby]

looks like cambridge btw

enrichment of 3B in the ext1 text

 

[cristal]

Yeah that’s right and then u make the equation greater and equal to 0 I think . Idk if that right but then u just solve for x with the inequality sign

no just greater than, 1/0 isn't valid

 

[cristal]

enrichment of 3B in the ext1 text

are you a walking cambridge

 

[Study to success]

enrichment of 3B in the ext1 text

So I’ll never be asked this in an adv exam right?

 

[jane1820]

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HELPP I CANT DO THESEE AHSHFHFJ

Domain:
Factorise the denominator then solve (root(whatever u got when factorised) > 0)
range:
u need to sketch it or use desmos/geogebra

 

[cristal]

bc you'd make a good bridging course

 

[jane1820]

bc you'd make a good bridging course

Plz Get out