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  1. kawaiipotato

    HSC 2016 MX1 Marathon (archive)

    Re: HSC 2016 3U Marathon Prove that a+b< c*sqrt(2) if a,b are two sides of a right angled triangle and c is the hypotenuse.
  2. kawaiipotato

    Inequality

    Triangle inequality
  3. kawaiipotato

    UNSW chit chat thread

    Re: UNSW chit chat thread 2016 Oo I was in the Ainsworth Building when the alarm started ringing and yeah everyone just walked out slowly
  4. kawaiipotato

    Rathin's Maths Help Thread

    $ Draw up a circle with radius one and centre at the origin$ $Draw a line from the origin to the circumference of the circle in the second quadrant.$ ($This will satisfy the condition$ \ \frac{\pi}{4} < \theta < \pi ) $Understand that$ \ \cos \theta \ $can be found by drawing a line down...
  5. kawaiipotato

    equation reducible to quadratic

    edit \frac{x^2 - 1}{x} - \frac{18x}{x^2 - 1} = 3 x \neq 0, \pm 1 $ multiplying by$ x(x^2 - 1) $throughout$ \Rightarrow (x^2 - 1)^2 - 18x^2 = 3x(x^2 - 1) (x^2 - 1)^2 - 18x^2 - 3x(x^2 - 1) = 0 x^4 - 2x^2 + 1 - 18x^2 - 3x^3 + 3x = 0 x^4 - 3x^3 - 20x^2 + 3x + 1 $Notice the...
  6. kawaiipotato

    range q

    \sqrt{ax+b} \geq 0 $for real values of a,b and all x in its domain$ \Rightarrow \frac{1}{\sqrt{ax+b}} > 0
  7. kawaiipotato

    Absolute value

    Because for |x-2|, for any number x>2 then x-2 > 0 and since x-2 > 0 then |x-2| = +(x-2) If x<2 then x-2<0 so |x-2| = -(x-2) = 2-x
  8. kawaiipotato

    I think your inbox is full haha

    I think your inbox is full haha
  9. kawaiipotato

    Log Quesiton help please!

    $ let $ y = \ln (\ln \left(e^{x}\right)) $ then $ y = \ln (x \ln e ) = \ln x $so$ y' = \frac{1}{x}
  10. kawaiipotato

    What apps r u using?

    play magnus, reddit is fun, tripview, youtube
  11. kawaiipotato

    ngo and sons entrance exam failed

    i believe yr 11 and yr 12 lets u join even if you failed the one given in yr 7 to 9
  12. kawaiipotato

    How long does it take you to travel to Uni?

    Around an hour for me. Couple of friends are having 1.5hr travel times
  13. kawaiipotato

    HSC 2016 MX2 Combinatorics Marathon (archive)

    Re: HSC 2016 MX2 Combinatorics Marathon Satisfy the condition first (group the R's) so that they look like RRREEAANG Treat the Rs as one group and so there are 7 'groups'. Arranging these groups, the amount of ways this is possible is 7!/(2!2!) (Dividing by 2! And 2! because there are two of...
  14. kawaiipotato

    I don't think I looked at your profile before this?

    I don't think I looked at your profile before this?
  15. kawaiipotato

    HSC 2016 MX2 Integration Marathon (archive)

    Re: MX2 2016 Integration Marathon Not a fan of IBP so I think there would be an alternate method $ let $ y^3 = x 3y^2 dy = dx $I$ = \int \cot ^{-1} y * 3y^2 dy $Using IBP, letting u $ = \cot ^{-1} y $and$ dv = 3y^2 dy $I$ = y^3 \cot ^{-1}y + \int \frac{y^3}{y^2 + 1} dy = y^3...
  16. kawaiipotato

    HSC 2016 MX1 Marathon (archive)

    Re: HSC 2016 3U Marathon $Question 1$ $ When the area in square units of an expanding circle is increasing twice as fast as its radius in linear units, what is the radius?$ $ Question 2 $ \lim_{t \rightarrow \infty} \left(4t^{2}\left(\sin \left(\frac{2}{t}\right)\right)^2 \right)
  17. kawaiipotato

    What course you doing next year?

    b actuarial studies @ unsw
  18. kawaiipotato

    Share your 2015 HSC results here

    Who else didnt get theirs yet? Did everyone here achieve their goals?
  19. kawaiipotato

    Survey- Impact of mathematical education on answering simple Mathematics questions

    Re: Survey- Impact of mathematical education on answering simple Mathematics questio done
  20. kawaiipotato

    Cambridge Prelim MX1 Textbook Marathon/Q&A

    Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread It's not a logarithm law. It's a variant of the quotient rule used in differentiation. Quotient rule: \left(\frac{u}{v}\right)' = \frac{u' v - v' u }{v^2} $ In this case, u = 1 and so u' = 0 $ Which will give you the rule...
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