Search results

Oh right because anticlockwise is in the positive direction

Every topic helped. The one that helped the least was probably complex numbers though.

Oops. You're right and it does affect the proof. Mine only works when it's actually "z^2 - a^2" but having "a^2" proved the result so I think it might be a typo.

arg(z^2 - a) = arg((z-a)(z+a)) = arg(z-a) + arg(z+a) = arg(z-a) - arg(z+a) + 2arg(z+a) ($I thought of doing this because it's easier to work with vectors if there's a negative sign$) $ Note that $ arg(z) = 2arg(z+a) $ by constructing vectors z-a and z and using the circle geometry...

arg(z-a)-arg(z-b)=θ, $ Pick an arbitrary point on the Argand Diagram and label this as vector z $ $ Assuming a,b are real, mark these points on the x-axis $ $ z-a means the vector starts from a to z and similarly for z-b $ $ arg(z-a)-arg(z-b) $ = \theta $notice the negative sign for...

Re: MX2 2016 Integration Marathon \int \frac{ \sin x}{ \sin x + \cos x} dx

Re: HSC 2016 2U Marathon Oops, yeah, changed n to 80

Re: HSC 2016 2U Marathon Yep fixed it haha

Re: HSC 2016 2U Marathon Question : \sum_{k=0}^{80} \frac{1}{ \sqrt{k+1} + \sqrt {k}}

Re: HSC 2016 3U Marathon Is there a limk to the backwards induction proof? Or is it on Wikipedia?

Re: HSC 2016 3U Marathon Where'd you get that question from?

What happened to him and CLG?

re: HSC Chemistry Marathon Archive Le Chatelier's Principle (LCP) states that a disturbance experienced by an equilibrium will cause the equilibrium to shift, in order to minimise the disturbance. In step 1, the mole ratio of gases of reactants to products is 9:10 and thus, to maximise the...

Re: HSC 2016 2U Marathon I think notes would still be useful for revision. Obviously 100% reliance on them wouldn't be efficient but it's not counter-productive (if that's what you're suggesting).

Re: HSC 2016 2U Marathon Why does having notes for maths mean it's not good?

Re: HSC 2016 4U Marathon - Advanced Level a^3 + 4a^2 b = 4a^2 + b^4 a^2 + 4ab = 4a + \frac{b^{4}}{a} ($dividing by a since a $ \neq 0 ) a^2 + 4ab + 4b^2 = 4a + \frac{b^{4}}{a} + 4b^2 (a+2b)^2 = \frac{4a^2 + b^4 + 4ab^2 }{a} (a+2b)^2 = \frac{(b^2 + 2a)^2 }{a} a = \frac{(b^2 +...

What'd you do for it?? I was a bit confused for that hahah

It was alright exam. Harder than I expected but it was good as it didn't focus too much on on area

My gradient was like 0.86

Ah cool. What was the numerical value? I think i remember it being 4. Something?