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i meant that the quantity Vq wold be negative since charge is negative i thought since Work = Vq and work is being done against the electrons (the direction of force is opposite to the direction of motion) which means that our work must be negative which implies that Vq is negative, which makes...

does that mean my method isnt valid? i believed i should be able to work normally with joules and then convert to electron volts once i finished

did you set Kmax = V instead of Kmax = Vq because we would eventually be dividing by q to convert into electron volts? however q is -1.602*10^-19, not 1.602*10^-19 if we assume that after division, a coefficient of -1 still remains as the charge is negative, we end up with the 3.282 eV result...

i did this photoelectric effect question a while ago but got a different answer to my teacher and the book it came from When yellow-green light with a wavelength of 500nm is shone on a metal, the photoelectrons require a stopping voltage of 0.8V. Calculate the work function of the metal in...

-e^(-x^2) cannot be integrated with respect to x using standard techniques of integration, it is known as the gaussian integral

no need to integrate the cumulative distribution function \text{Cumulative distribution function }=F(x)=\int_{a}^{x}{f(x) \, dx, \text{ where }f(x)=\text{Probability density function} and f(x) has domain [a,b] for some P(X < q), you can just evaluate in F(q) to get the answer, no integration...

why not

hello friend if youd like here is the working for initial velocity in terms of range and launch angle, sorry if it is wrong but it was 2:30 am so i had to answer this to avoid sleep

no need to get all fancy

@jimmysmith560 dont be sad its like when your favourite teacher yells at you ya know it made me very sad here are more notes and also a gift https://www.acehsc.net/resource/extensive-notes-for-yearly-exam-topic-1-7/ https://www.acehsc.net/resource/notes-for-yearly-exam-mikayla-carey/

https://www.acehsc.net/resource/summarised-prelim-agriculture-notes/ also incredibly rare jimmysmith L for deleting my amish paradise video

what on earth is a military grade pen

not related to the thread but your son must be a beast at math lol

i see, i dont know why i never considered that the functions could be different, thanks for the help (p.s i wonder if there is some kind of shared properties that g(x) and f(x) have that allow their areas under the graph from a to b to be equal even though g(x) != f(x), or if it is just a matter...

the implication from this is that \tan^{-1}{(\frac{x(1-x)}{2-x})}=\frac{1}{3}\tan^{-1}{(x)} (bounds of integration are unchanged so both integrands must be equal) however an investigation on desmos shows this is not at all the case what magic is going on here??

^

if you're finding when (3P)/(200) - K = 0, that means you are finding when dP/dt = 0 (a stationary point on the graph). when the derivative equals 0, it does not necessarily mean that the population is 0.

i thought continuous variable were those that could take any value on the number line. but if we show that this variable can't take a value of sqrt2, which lies on the number line, the variable must not be a continuous variable. am i right in saying this?

but for the case of Field goals made divided by field goal attempted, or Free throws made divided by free throw attempted, how could you ever get a result of sqrt2 ?