Re: Discrete Maths Sem 2 2016
$ Suppose $ \log_n m = \frac{a}{b} $ where a,b $ \in \mathbb{R}.
$ This implies that $ m^b = n^a
\therefore m = a^{\frac{a}{b}} = a^k $ as $ \frac{a}{b} \in \mathbb{Q}.
$ Consider the converse. $ m = n^k
$ Since k $ \in \mathbb{Q} $ that means it can...