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Good movie? Yes. Though him leaving that 'planet' pretty much soon after arriving there was a bit silly imo. Sequel? No. Nope.

Yes, that works =)

I've just uploaded the paper + all solutions + marking criteria. Please note that the final version of the paper differs slightly from the original paper that you sat.

Here is the results thread! http://community.boredofstudies.org/1094/general-discussion-2015-hsc/343889/extension-2-bos-trial-2015-results-documents.html#post7051009

Hi all Please find below the student numbers and the marks that each student received, as well as the statistics for this year's Extension 2 BOS Trials. We will be uploading the paper and the solutions/marking criteria/markers comments as soon as they're ready (we are working on those at the...

Making the results thread now.

They'll be posted in a new thread.

;-)

Considering the average relative to the difficulty of the paper, I think last year's and this year's are roughly equal in strength. They will. The process is bottlenecked by solutions but we already have all the data ready to go. For MX2 Avg 2013: 44.7 Avg 2014 39.7 Avg 2015: 38.6

We've finished marking Extension 2 and are just finalising solutions/criteria/comments etc now. We're nearly done with 2U as well.

Alternatively, you could just think "Am I going to regret saying this in the future?" before making a post. That would solve a lot of problems actually.

Re: HSC 2015 4U Marathon I suppose this also 'uses the modulus', but it is essentially backdooring glittergal's solution. \\ \frac{a+bi}{c+di} = i(bc-ad) $ and $ \frac{c+di}{a+bi} = i(ad-bc) $ which in laymans terms means that $a+ib$ and $c+id$ represent all perpendicular unit vectors...

Re: HSC 2015 4U Marathon Glittergal's solution implicitly does when expressing the points as functions of theta and phi, as they represent points on the unit circle.

On Sunday/Monday Night. The solutions/paper/marking criteria/markers comments etc will also be released then. If you do not wish to receive you mark back, you can always not check the results in the thread =)

He is trying to prove the conjugate root theorem for polynomials of degree 2. Stating the theorem to prove it is a bit redundant. Your response would be more appropriate for a question styled as "Explain why ....", not "Show that ..." Yes.

Start with the given expression and conjugate both sides. From there, use your conjugate rules to slowly 'spread' the conjugate symbol across all terms to obtain the required result.

Re: 2015 permutation X2 marathon It was touched on in the 2005 Maths Advanced paper Q10 (b).

We considered it, but didn't get anything nice out of it. But notice that the 2U and 3U probability questions were 'game' questions (about having a run of length K), which is similar in flavour I suppose.

Re: MX2 2015 Integration Marathon No? Tabular integration by parts is mechanically identical to repeated applications of integration by parts. It just arranges things in a neater manner (the table) that makes the iterations a lot cleaner to work with.

Re: MX2 2015 Integration Marathon In (c) your integral does not depend on 'r'. Should that be V_n?